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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: range
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[Post New] 7 Jun 2007 18:18:45 IST
   Subject: Re:range
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HIMANSHU JAIN (376)

Olaaa!! Perrrfect answer. 62  [95 rates]
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u must have written /2 + tan-1x.
which is true but to define sin-1x , x should be (-1,1)
& tan-1x could be (-/4,/4) only.
so ans is (/2 - /4 , /2 + /4)
i.e. (/4,3/4)
 
Himanshu Jain P.E.C. http://jainhim.blogspot.com/
  this reply:   5 points  (with 1  Olaaa!! Perrrfect answer.   in 1   votes   )     [?]
 
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