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akki ~~ unlucky forever ~~ (1635)

Olaaa!! Perrrfect answer. 275  [405 rates]

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put\ x=acos\theta\\ \\ I=a^2\ \int_{0}^{\frac{\pi}{2}}\theta^2sin^2\theta\ d\theta\\ \\ or\ I = a^2\ \int_{0}^{\frac{\pi}{2}}cos^2\theta\ (\theta^2+\frac{\pi^2}{4}-\theta\pi)d\theta\\ \\adding\ both\\ \\ I=\frac{a^2}{2}\int_{0}^{\frac{\pi}{2}}(\theta^2+\frac{\pi^2}{4}cos^2\theta-\pi\theta\ cos^2\theta)d\theta

 

now,all 3 integrals are easily seperately integrable  . . .


all's well that end's well, but if it dosen't, then it is not the end . . .
  this reply:   15 points  (with Olaaa!! Perrrfect answer.   in 3   votes   )     [?]
 
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