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Author
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Message
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24 Jul 2009 19:38:29 IST
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1000 = 1 + (n-1) dso n = 1 + 999/dn shud be integer ..same wid d(bcz no element of AP is in fraction).....so d shud be factor of 999.....which r 1,3,9,27,37,111,333....not possible further i think as elements shud be atleast 3....so 7 i think...hence option 4....
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