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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: log inequalities
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[Post New] 19 Jun 2007 22:58:56 IST
   Subject: Re:log inequalities
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HIMANSHU JAIN (376)

Olaaa!! Perrrfect answer. 62  [95 rates]
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case 1)      x>1
 2x - 3/4 >x2
(2x-3)(2x-1)<0
x (1/2,3/2)
 
but acc to case ans for case is
x  (1,3/2)
 
case 2)     0<x<1
(2x-3)(2x-1) >0
 x  (-,1/2)  (3/2,)
 
acc. to case ans is (0,1/2)
 
net result is
x  (0,1/2)(1,3/2)
Himanshu Jain P.E.C. http://jainhim.blogspot.com/
  this reply:   7 points  (with 1  Olaaa!! Perrrfect answer.   in 2   votes   )     [?]
 
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