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Reply Forum Index -> Integral Calculus originally posted here on IIT-JEE / AIEEE community   
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Himanshu Garg (0)

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Integrate

from 1 to 2.5        [ x ] dx             where [ ] is greatest integer function.

    
mardav, NIT-B civil engineering. (451)

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integrate it by dividing the limit into intervals. (0,1) then (1,2) and last (2,2.5). ur answer will be 0+1+1 i.e 2
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HIMANSHU JAIN (376)

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Try to analyze it's graph.

Check the graph on this link:

http://library.thinkquest.org/20991/alg2/graphs.html

now, u'll get to know that [x] is 1 for (1,2) and 2 for (2,2.5).

so, u'll get :

1.dx for (1,2) = 1

and 2.dx for (2,2.5) =1.

So, ans is 2.

Do ask again if any doubt is there.


Himanshu Jain
P.E.C.
http://jainhim.blogspot.com/
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Deepak Aggarwal (3759)

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This is the graph of greatest integer function (or the floor function).

Now break the limit for the integral first from 1 to 2 and then from 2 to 2.5.

I = int x from 1 to 2.5 [x] . dx

I = int x from 1 to 2 [x] . dx + int x from 2 to 2.5 [x] . dx

I = int x from 1 to 2 (1) . dx + int x from 2 to 2.5 (2) . dx

I = limit from 1 to 2 (x) + limit from 2 to 2.5 (2x)

I = (2 - 1) + 2(2.5 - 2) = 2 (Ans)


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