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gaurav saini (193)

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 what is the derivative of sin(x^0)

    
siDDhESwaR MuKhErjEE (358)

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I guess the derivative would be 0 since the given expression is a constant

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gaurav saini (193)

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 i am not sure but i think its not 0

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HIMANSHU JAIN (376)

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It is zero.

look, it this way:

derivative:  Cos(x^0) multiplied by derivative of x^0.

which is zero.

I hope I am clear..


Himanshu Jain
P.E.C.
http://jainhim.blogspot.com/
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siDDhESwaR MuKhErjEE (358)

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yup it has to be zero........basically the thing is derivatives of such functions cannot be found out.
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» ÆoniuM XEonAX « (211)

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Derivative:


 



d/dx(sin(x^0)) = 0

 





Possible derivation:\nd/dx(sin(1))\n | The derivative of sin(1) is zero:\n= | 0

 





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