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29 Mar 2010 12:25:15 IST
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29 Mar 2010 12:39:28 IST
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imagining a=b is wrong here ....if these 2 are variables .....den write b as a only!!!/.............for example if i say ................................... BLUE GENE = OSAMA BIN LADEN!.............the assumption is wrong here!!!....or is it??
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29 Mar 2010 12:43:06 IST
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we all have been studying from almost class 5 that x/0 is undefined or infinite ,so when u r dividing (a+b)(a-b)=b(a-b) by (a-b) which is equal to 0 u r doing the wrong thing <<<<<<<
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29 Mar 2010 13:35:07 IST
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when u r dividing (a-b)..as a=b.. this is zero... and dividing by zero is nt defined... hence step 3 is wrong
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29 Mar 2010 16:19:20 IST
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It is exactly same as: 0*2 = 0 *15 so, cancelling 0s on both sides, u get 2=15. I hope you know now where the mistake lies.
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Himanshu Jain
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http://jainhim.blogspot.com/ |
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29 Mar 2010 17:35:23 IST
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Yes you cannot cancel a-b from both sides as you are saying a=b.
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29 Mar 2010 18:40:02 IST
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Thanks everyone. :-)
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14 Apr 2010 18:34:57 IST
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If a=b,then dey both will cancel and 1=1.
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16 Apr 2010 05:40:32 IST
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we can assume
a = b
Now, ab = b2
=> ab - a2 = b2 - a2
=> a (b - a) = (b + a)(b - a) [error is in this step]
since, a = b
=> b - a = 0
when we divide both sides by (b - a) then actually what we do is :-
a x 0/0 = (b+a) x 0/0
but, 0/0 form is not defined which is also known as indeterminate form.
So this is the error!............
if 0/0 = 1 then 0 x 2 / 0 x 3 = 1 => 1 = 2/3, which is not possible
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16 Apr 2010 10:50:02 IST
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@Rahul: The people who've answered above haven't said anything different.
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19 Apr 2010 18:19:34 IST
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hey man a-b = 0 . So u cannot cancel from both sides. Thats quite simple
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19 Apr 2010 18:27:35 IST
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dont worry yaar jee mein ye sab nahi aaega .....so leave it !!
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