Probability problem

total outcome = 6⁶

 favourable = (1*2*3*4*5*6)*6!

p=(5!)² /6⁴

it should be 6!/(6^6) which is equals to 0.0154.

lets say 1 occurs on all...

so P(1) = 1/6  *  1/6  * 1/6  *  1/6  *  1/6  *   1/6    (for all six die)

and this can happen 6 times for {1,2,3,4,5,6} so (1/6  *  1/6  * 1/6  *  1/6  *  1/6  *   1/6)  * 6.............ans!!

i.e. 1 / 6⁵ ans!!

Let us use classical definition of probability to keep it simple.

n(E) = 6!  because (1,2,3,4,5,6) can be arranged in 6! ways.

n(S) = 6^6 because total no. of outcomes is 6^6.

So,